/* slowmult.c
   demonstrates slow multiplication by iteration
   Richard Kay 29 April 1999 */

#include <stdio.h>
#include <conio.h>

int main(void){
  double store,num;
  long int p,n;
  printf("enter a number and an (positive int) power to raise it to\n");
  scanf("%lf%ld",&num,&p);
  store=num;
  if(p>1)
    for(n=1;n<p;n++)
      store*=num;
  printf("the result is %15.6lf\n",store);
  printf("press a key to continue\n");
  getch();
  return 0;
}